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jj16802
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    algebra/trig2

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    Post by preid1220 Wed Sep 15, 2010 6:51 pm

    well as it goes, i forgot most of what i sleep threw last year due to staying up multiple days in a row, so this will be my all purpose cry for help =D . first order of business, does anyone know how to do this problem, and if you do can you give me the steps to do it?

    x^2-2x>0

    ^i am sure i look like an idiot right now lol.
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    Post by Ahmed Wed Sep 15, 2010 6:54 pm

    Yes you do look like an idiot. BUT luckily Im here to help Very Happy

    Lol JK Razz

    What exactly is the question asking?
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    Post by preid1220 Wed Sep 15, 2010 6:55 pm

    i need to find x, and i just cant get my head quite around foiling, i blame the idiot who sits next to me and needs the teacher attention 24/7
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    Post by Justice Wed Sep 15, 2010 7:02 pm

    x^2-2x>0
    x(x-2)>0

    Break it into intervals (-∞,0)∪(0,2)∪(2,∞+)
    and you pick a number from each interval to check which satisfy it.
    so.....
    Pick -10 for the first interval
    (-10)(-10-2)>0
    true! thus we know (-∞,0) is one interval

    Pick 1 for(0,2)
    (1)(1-2)>0
    false!
    thus we know (0,2) is not one interval

    pick 100 for the final interval
    (100)(100-2)>0 true!

    Thus the answer is (-∞,0]∪[2,∞+)
    [ means inclusive and ( means exclusive
    If you have any questions post
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    Post by Ahmed Wed Sep 15, 2010 7:03 pm

    x^2-2x>0
    x(x-2)>0
    x>2

    x^2-2x<0
    x(x-2)<0
    x=1

    This is if I remember everything correctly. I asked Lev to check.
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    Post by Ahmed Wed Sep 15, 2010 7:04 pm

    And he did it before me.

    Take Lev's answer. My brain is still on vacation mode. Espcially with this lack of HW.

    @Lev: You don't multiple the inequality by -1 to get the other answers?
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    Post by Jewelz Wed Sep 15, 2010 7:13 pm

    What grade are you in Ahmed? Your only in Algebra 2 :O
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    Post by Ahmed Wed Sep 15, 2010 7:16 pm

    I'm in AP Calculus AB
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    Post by Justice Wed Sep 15, 2010 7:29 pm

    You should trust me...I told Ahmed of a dude who teaches this stuff listen to him....I am not sure if i can say his name


    Last edited by Justice on Wed Sep 15, 2010 7:30 pm; edited 1 time in total (Reason for editing : Typing really fast lol)
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    Post by Ahmed Wed Sep 15, 2010 7:34 pm

    OK Lev Rolling Eyes

    This isn't really hard...it's just that my brain is a bit rusty at the moment. Still need to go into school mode.
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    Post by preid1220 Wed Sep 15, 2010 7:35 pm

    thanks Lev,thanks to you i see what i have been missing =D
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    Post by Ahmed Wed Sep 15, 2010 7:54 pm

    Oh I remember doing this with Arjun now when he used to draw +s and -s on the ones that worked or not...

    Well I'm in Cal now so w/e lol.

    Anyways thanks for helping him out Lev the math noob.
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    Post by Fangy Wed Sep 15, 2010 8:37 pm

    Lev's answer is so complicated. xD
    |x| is greater than or equal to 2 is a million times easier to read.
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    Post by jj16802 Wed Sep 15, 2010 9:00 pm

    OMG please never remind me of this horrible class Evil or Very Mad
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    Post by preid1220 Wed Sep 15, 2010 9:51 pm

    jj16802 wrote:OMG please never remind me of this horrible class Evil or Very Mad

    bad day in math for you as well?
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    Post by jj16802 Wed Sep 15, 2010 9:59 pm

    Couldn't get some of the problems, just like I did in 9th grade. It's the recipe for disaster.
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    Post by Ahmed Wed Sep 15, 2010 10:02 pm

    Ask the teacher?
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    Post by preid1220 Wed Sep 15, 2010 10:09 pm

    Ahmed IV wrote:Ask the teacher?

    the teacher is useless lol.
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    Post by Ahmed Wed Sep 15, 2010 10:58 pm

    Go to another math teacher.
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    Post by jj16802 Thu Sep 16, 2010 4:12 pm

    Every math teacher I had in high schools makes more jokes than teach the actual stuff Hilarious
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    Post by Ahmed Thu Sep 16, 2010 6:22 pm

    ^^^That's my orgo teacher.
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    Post by preid1220 Sun Sep 19, 2010 5:21 pm

    reviving this, factor this completely so i can check myself

    2x^2-18x-72

    and

    12x^3+2x-30x-5


    also another inequality like before

    |2x-7|<9
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    Post by Ahmed Sun Sep 19, 2010 5:31 pm

    2(x-12)(x+3)

    Did you write the second one correctly? Check it.

    Inequality solution: 0 is less than or equal to x. x is less than or equal to 4.
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    Post by preid1220 Sun Sep 19, 2010 6:36 pm

    it's right
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    Post by Ahmed Sun Sep 19, 2010 6:51 pm

    So why didn't you write: 12x^3+-28x-5 ?

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