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    Algebra/Trig Competition Ahmed VS Lev

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    Post by Justice Thu May 13, 2010 6:50 pm

    I will give you the honor of starting =]
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    Post by Ahmed Thu May 13, 2010 6:55 pm

    Okey Dokes Young one Razz
    ================================
    Let's start out easy:

    Rewrite the expression as an algebraic expression in x:

    cos(sin^-1 (x) + cos^-1 (x))
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    Post by Justice Thu May 13, 2010 7:01 pm

    Zero
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    Post by Ahmed Thu May 13, 2010 7:02 pm

    Show your work man. Wink
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    Post by Justice Thu May 13, 2010 7:39 pm

    solution:
    cos(x+y)= cosxcosy-sinxsiny
    cos(sin^-1x + cos^-1 x)

    Let sin^-1x = u
    Let cos^-1 x= v

    cos( u + v) = cos u cos v - sin u sin v = cos(sin ^-1x) cos (cos-1x) - sin( sin^-1x) sin (cos -1x)

    ok so... we know sin(sin-x) and cos(-x) are both equal to x and cos(sin ^-1x)= sin (cos -1x)
    so we can assume x-x=0


    Last edited by lev_93 on Thu May 13, 2010 7:53 pm; edited 1 time in total
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    Post by Ahmed Thu May 13, 2010 7:46 pm

    Ok Im waiting and it seems you got it. Very good.

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    Your turn.
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    Post by Justice Thu May 13, 2010 7:57 pm

    Here is something easy
    Simplify
    (2x^2+(3a+4b)x+a^2+3ab+2b^2)/(x^2+(a+b-2)x-2a-2b)

    Hint: it can be done Wink
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    Post by Ahmed Thu May 13, 2010 8:06 pm

    Thanks for the hint Smile

    (a+2(b+x))/(x-2)

    I don't think there is a point in showing work for a simplifying question.

    Good?
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    Post by Justice Thu May 13, 2010 8:13 pm

    I not very smart. I think you maybe need to explain it to me?
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    Post by Ahmed Thu May 13, 2010 8:16 pm

    Comon man. It's annoying writing it on the computer. Ill show you tomorrow in class you noob Rolling Eyes

    Could it be my turn? Very Happy
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    Post by Justice Thu May 13, 2010 8:18 pm

    ok fine but i better be right!!
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    Post by Ahmed Thu May 13, 2010 8:19 pm

    Right about what?
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    Post by Justice Thu May 13, 2010 8:22 pm

    Your solution of course. Go on with your question please....
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    Post by Ahmed Thu May 13, 2010 8:29 pm

    Of course Im right. You should have known the answer BTW. :S

    Find the partial fraction decomposition of the rational function:

    (2x-4)/(x(x-1)^2)
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    Post by The Banker Thu May 13, 2010 8:33 pm

    ahmed dear, ur over confident.. Razz
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    Post by Ahmed Thu May 13, 2010 8:35 pm

    Rolling Eyes

    What did I do? All I am doing is answering and asking Qs.
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    Post by The Banker Thu May 13, 2010 8:36 pm

    + da "i'm betta than all of u" attitude Rolling Eyes
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    Post by Ahmed Thu May 13, 2010 8:40 pm

    I have no attitude. And I never said that. I just said I know more than you.
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    Post by The Banker Thu May 13, 2010 8:41 pm

    lolz.. big difference Rolling Eyes

    kay dear.. i'll watch the ownage Razz
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    Post by Ahmed Thu May 13, 2010 9:02 pm

    Ahmed:1
    Lev:1

    I think Lev doesn't know this one Razz

    You could always give up Lev Wink
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    Post by Justice Thu May 13, 2010 9:12 pm

    Your are kidding right?? Do you know how long this took me?!?

    (-4+2 x)/((-1+x)^2 x) = q_1/(x-1)+q_2/(x-1)^2+q_3/x
    2 x-4 = (x-1)^2 q_3+x (x-1) q_1+x q_2
    2 x-4 = x^2 (q_1+q_3)+x (-q_1+q_2-2 q_3)+q_3
    -4 = q_3
    2 = -q_1+q_2-2 q_3
    0 = q_1+q_3

    Solve the system which took awhile:
    q1=4
    q2=-2
    q3=-4

    -4/x+4/(x-1)-2/(x-1)^2
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    Post by Ahmed Thu May 13, 2010 9:19 pm

    Very nice Lev! Good Job

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    Now I actually have sympathy for you not getting into AB Cal...I now know you truly are a good candidate for it...but anyways, let's continue our competition.
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    Post by Justice Thu May 13, 2010 9:29 pm

    I think it was just the stupid system that the school uses cause Daniel got in and he is in my class and has like a 85 average.

    Anyways...

    If the probability of an event occurring is x and the probability of it not occurring is 6x^2, what is the value of x. this is simple
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    Post by Ahmed Thu May 13, 2010 9:34 pm

    He told me he has a 90...but yeah he is a dumb***. Anyways, I do know the reason why you didn't get in...my English teacher told me. She was obviously talking for AP English, but ti seems like they did it for all. She told us that they maximized the class, but the number of applicants doubled from prior years so instead of traditionally looking at just the subject grade (math or English) they looked at your accumulative grade since freshman year. :S
    ===================================================================
    x+6x^2=1
    6x^2+x-1=0
    (2x+1)(3x-1)=0
    x=-1/2, 1/3
    Reject -1/2

    Good?
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    Post by Justice Thu May 13, 2010 9:40 pm

    It should really matter what your overall is. Math is the only subject that has something to do with Math. You cant compare oranges with apples. Plus we have about the same overall average.

    yes good
    Another one??

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