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    Algebra/Trig Competition Ahmed VS Lev

    Ahmed
    Ahmed
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    Post by Ahmed Sat May 15, 2010 8:57 pm

    In right triangle PQD: tan47=h/y ---->h=ytan47 [1]

    In right triangle PQE: tan36=h/x ---->h=xtan36 [2]

    Equate [1] and [2]: ytan47=xtan36 ------->y=tan36x/tan47 [3]

    In right triangle DQE: x^2+y^2=70^2

    Substitute [3]: x^2+ (tan36x/tan47)^2= 4900 ---> x^2(tan^2(47)+tan^2(36))/tan^2(47))=4900

    x= 70tan47/ sqr root:tan^2(47)+tan^2(36)

    Substitute into [2]: h=tan36/tan47 * 50tan47/ sqr root:tan^2(47)+tan^2(36)

    And the answer is 39.26304499 (I calculated it wrong the first time)
    Justice
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    Post by Justice Sun May 16, 2010 10:58 am

    Where is point Q? Can you draw your triangle with all the angles labeled please?
    Justice
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    Post by Justice Sun May 16, 2010 11:00 am

    The reason I am asking is because i think you did it wrong.
    Ahmed
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    Post by Ahmed Sun May 16, 2010 11:36 am

    I already did on the previous page
    Justice
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    Post by Justice Mon May 17, 2010 6:56 pm

    Fine Ahmed. If you solve this i officially will says you are better then i am for now.

    team 1 and team 2 work on a project for 15 days. team 3 then comes to help them which the project was done in 5 days. the daily output of the 2nd team is 20 percent more than that of the 1st team. the second and 3rd team could do the jobs in .9 the time the first and third team to do it together. How much time would it have taken if all three teams worker together in the start?
    Ahmed
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    Post by Ahmed Mon May 17, 2010 6:59 pm

    I hate these world problems...Ill solve it after the AP exam lol
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    Post by Justice Mon May 17, 2010 7:09 pm

    Good luck with your APs...
    Ahmed
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    Post by Ahmed Mon May 17, 2010 7:10 pm

    Thanks. Good luck to both of us on the Regents and SATs.

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