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I'll allow you to start.
Last edited by Ahmed IV on Wed May 12, 2010 10:51 pm; edited 1 time in total
+2
The Banker
Ahmed
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Trig Competition-Ahmed vs. Marwa
Ahmed- NH Admin
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Last edited by Ahmed IV on Wed May 12, 2010 10:51 pm; edited 1 time in total
The Banker- NH Member
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- Spoiler:
- The diagram shows part of the equation y=f(x), where f(x)=1+2sin(px+q), p and q being positive constants and q≤90. The curve cuts the y-axis at the point A and the x-axis the points C and D. The point B is a maximum point on the curve.
Given that the coordinates of the point A and C are (0,2) and (45,0) respectively
>> calculate the value of q
>> show that p=4
>> fine the coordinates of B and D
Ahmed- NH Admin
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1 Question at a time:
f(x)=1+2sin(px+q)
0=1+2sin(p(0)+q)
0=1+2sin(q)
sin(q)=-1/2
q=sin^-1(-1/2)
q=-30 degrees
f(x)=1+2sin(px+q)
0=1+2sin(p(0)+q)
0=1+2sin(q)
sin(q)=-1/2
q=sin^-1(-1/2)
q=-30 degrees
The Banker- NH Member
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close...
but its q=30
but its q=30
Ahmed- NH Admin
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Well you can't blame me to be honest. You never specified the range...for example: 0<x<360
You just said "find"...so I won
My turn?
You just said "find"...so I won
My turn?
The Banker- NH Member
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lol, kay mr 
ur go
ur go
Ahmed- NH Admin
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Ahmed:1
Marwa:0
Let's start out easy:
Is x-1 a factor of x^567-3x^400+x^9+2?
Marwa:0
Let's start out easy:
Is x-1 a factor of x^567-3x^400+x^9+2?
The Banker- NH Member
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nope
Ahmed- NH Admin
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Show your work. I showed my work.
The Banker- NH Member
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the factor theorem,
(x-1) so we'll use x=1
1-3+1+2 =/= 0
so (x-1) is not a factor of the big long thing u wrote up there...
(x-1) so we'll use x=1
1-3+1+2 =/= 0
so (x-1) is not a factor of the big long thing u wrote up there...
Last edited by Marwa on Thu May 13, 2010 2:55 pm; edited 1 time in total
Ahmed- NH Admin
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Good.
Ahmed: 1
Marwa: 1
Your turn.
Ahmed: 1
Marwa: 1
Your turn.
The Banker- NH Member
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i'll give ya the next q tomoz...
Ahmed- NH Admin
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I'm waiting.
Fangy- NH Retired Moderator
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Can I give a totally unrelated question to all of you, with some trig in it?
Ahmed- NH Admin
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Make another topic about it. This topic is just for a competition between Marwa and I to see who's smarter in Trig
Fangy- NH Retired Moderator
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Mmkay. Maybe I'll make it my next question in my quiz...
Ahmed- NH Admin
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Oh shouldn't I have won by now?
Fangy- NH Retired Moderator
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I extended it It ends this Saturday. Hoping for more answers.
It ends this Saturday. Hoping for more answers.
Ahmed- NH Admin
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Did anyone else answer? Just wondering.
Doc- NH Member
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i foresee marwa dominating this competition .. afterall, all she is good at is math lol
Ahmed- NH Admin
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I'm better (no arrogance meant lol). And I'll prove that. That's why I made this competition
Doc- NH Member
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u hardly know anything 
and if you're so good then challenge me to anything ...
and if you're so good then challenge me to anything ...
Ahmed- NH Admin
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I don't want to glorify myself to the point where I beat a 2nd year college student. But if you insist, then prepare for a humiliating defeat.
Doc- NH Member
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name the topic .. mentally destroying and completely embarrassing a youngster will be most entertaining .. prepare for the shame and despair ... only lamentation is in your future lol
Ahmed- NH Admin
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Well I wouldn't exactly be losing anything or being embarrassed since I am a "Junior" and you are a 2nd year college student
However, I could only gain. And that is being showing that I am smarter than you. So it's only your loss and my gain
However, I could only gain. And that is being showing that I am smarter than you. So it's only your loss and my gain
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