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    SAYF HELP NEEDED! URGENTLY!!!!!!!!!!!!!!!!!!!!!!(CHEM)

    Ahmed
    Ahmed
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    Post by Ahmed Wed Apr 21, 2010 10:01 pm

    I am about to stab this question. WHY IS THIS NOT POSSIBLE TO SOLVE???

    MnO4- + C2O4-2---> CO3-2 + MnO2(s) (basic)

    Write the balanced half reactions and overall net ionic equation.

    I did this:

    3e- + MnO4- + 4H2O---> MnO2 +2H2O +4OH-

    8e- + C2O4-2 + 6H2O ---> 2CO3-2 +3H2O + 6OH-

    Why the heck are both of them being reduced???!??!!!?!? What happened to the oxidation half-rxn?
    Doc
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    Post by Doc Wed Apr 21, 2010 11:07 pm

    o man i HATED half rxns ... but i think u added the 3e- to the wrong side in the first half rxn ...
    Ahmed
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    Post by Ahmed Wed Apr 21, 2010 11:10 pm

    They are easy. And I could do them, but this one doesn't work for soem reason.

    And no I added them to the right side. If you add all the charges on both sides, they are equal.

    Left= -4 | Right= -4
    Doc
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    Post by Doc Wed Apr 21, 2010 11:13 pm

    umm u def added one of them to the wrong side Rolling Eyes

    they r supposed to cancel out Rolling Eyes
    Ahmed
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    Post by Ahmed Wed Apr 21, 2010 11:14 pm

    I know that Sherlocks lol

    But did it correctly though.
    Doc
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    Post by Doc Wed Apr 21, 2010 11:15 pm

    thats y u ddint get the right answer? Rolling Eyes

    u have 3e and 8 e on the same side Rolling Eyes
    Ahmed
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    Post by Ahmed Wed Apr 21, 2010 11:17 pm

    I know, that's where my problem is.

    If you solve it, you will get the same 2 half-equations that I get.
    Ahmed
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    Post by Ahmed Fri Apr 23, 2010 8:00 pm

    I know what I did wrong now lol.

    Notice that the "O"s weren't balanced in the second equation >.<

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