If you were to study for an important test on Algebra, which Algebra topics would you study or focus more on?

P.S.: State specific topics.

facotring .. solving for the unknown variable .. graphing ..functions ..

i have a precalc review quiz .. what do i study for? lol ..

everything, obviously

I forgot to mention that you have less than a week to study.

we will help you,... by chearing you on cus i stink at math =D

On help on functions anyone?

have you done functions?

what kind of help? (help solving, expalaining, etc)

Sayfullah wrote:have you done functions?

You see Sayf...I am sure, some people forget the things that they learned last year.

This whole year I took geometry...all of a sudden I am taking an algebra test...so you forget things...

I took it before however.

Give me an example of a function question Hassan.

An easy one .. f(x) = 5x-3

Solve if x = 4

Lol, those are functions??

Those are th easiest questions

x=17

COrrect?

lol that was an extremely easy and simple one ....try tis one:

if f(x) = x^2+2x+3 find

f(x + h) - f(x)
-------------
h

*Note* this is a fraction ...

Wait...are these 2 questions?

Also what's the "h"?

I forgot to mention inequalities and absolute values ... might wanna try those too ... and rationalizing, complteting the square, exponents, radicals, simplifying ... a few more problems:

rationalize the denominator:
1
---
√x - 1

simplify:

(27x^3)^2/3

x+1 x^2-2x+1
----- * --------
x-x^2 x^2-1

*Note* the above problem is a fraction .. it's the same thing as x+1 / x-x^2 * x^2-2x+1 / x^2-1


solve for x

2x^2 + 1 = 4x

And forget that last problem I gave you .. that's actually more related to calculus than algebra ... here's a better problem related to functions:

find the domain of:
f (x) = 15 / x-3
or
15
----
x-3

1
---
√x - 1



√x - 1
-------
x- 2√x +1

Correct?

(27x^3)^2/3 ==I don't believe I took this...but refersh my memory please.

x+1 x^2-2x+1
----- * --------
x-x^2 x^2-1==This isn't clear...is that 1 fraction or 2?

I am stuck with the 4th one, is it correct so far: 2x^2-4+1=0

What do you mean find the "domain"?

first one is actually:
√x+1
--------
x-1

when you rationalize a problem like this you multiply both the numerator and denominator by the conjugate of the denominator ... the conjugate for the denominator for this problem is √x + 1 .. since the original denominator was √x - 1 .. the conjugate is basically the opposite of the original term ...

(27x^3)^2/3 ==I don't believe I took this...but refersh my memory please.

iut's 27x raised to the third power in paranthesis all raised to 2/3 .. if you haven't taken it just forget it ...

x+1 x^2-2x+1
----- * --------
x-x^2 x^2-1==This isn't clear...is that 1 fraction or 2?

this is just like the one you posted in the HW forum ... multiplying two fractions ...

I am stuck with the 4th one, is it correct so far: 2x^2-4+1=0

yeah you're right so far ... except you forgot to put the x after the 4 .. it's 2x^2-4x+1=0 not 2x^2-4+1=0 ... try using the quadratic formula for that ...

What do you mean find the "domain"?

you don't know what the domain, range and stuff are?

I thought you had to use FOIL, as in (√x + 1)(√x + 1)...when multiplying such things?

Ok, is it:

(x-1)
------
x(1-x)

=========================
Yes, I just forgot to write the x, when posting it here.

How would you solve it...there are no factors that fit 2x^2-4x+1=0...
=========================
I do, but I don't understand what do you eman by solve for them?

Aren't they for graphing?

argh just forget it man .. just study whatever you learned

Could you give me real questions...I am studying right now from a Barron's book.

You know...my weakest skill in math is not beign able to focus...my mistakes are always the stupidest mistakes...such as not reading a word like "false" or "true" or "right angles" *sigh*

|3-6x|>1
state in interval notation
the long vertical lines are absolute value brackets

x>-4/6

nevernmind ...

Is it right -___-?

ok this one

4x 6
--- * ----
x^2-9 x^2+x-12