In a series parallel circuit how do you find the voltage drop across a branch...this is urgent help!!!
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Hassan wrote:I am really sorry bro I can not help with this one. Have not taken physics for like at least 4 years....Good Luck in finding the answer.
Ahmed IV wrote:Sayf, what?
wilku_88 wrote:UR6= Ucc * R6 / (R4+R6+R7) and the Ucc is the battery voltage... simply voltage divisor
Ibn Rushd wrote:
This is the correct notation:
R1||(R2+R3||[(R8+R9)||R7+R5||(R4+R6)])
** "||" =the parallel sign
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