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In a series parallel circuit how do you find the voltage drop across a branch...this is urgent help!!!
In a series parallel circuit how do you find the voltage drop across a branch...this is urgent help!!!
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Electric HELP!!
Ahmed- NH Admin
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Steve- NH Member
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use a Voltmeter?
Ahmed- NH Admin
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No, I mean by pictures. this is basically the question:
Please tell me the how to find the voltage of R6
Please tell me the how to find the voltage of R6
Steve- NH Member
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does the voltage half at every break off?, but the voltage would increase where r9 rejoins
Ahmed- NH Admin
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I wish I could burn this question -___-
==============
All I know is that in a parallel circuit the voltage across parallel branches are the same.
And no it does not half at every branch...
The voltage doesn't neccessarly have a pattern other than at the end they must equal the total voltage (which is 60V).
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All I know is that in a parallel circuit the voltage across parallel branches are the same.
And no it does not half at every branch...
The voltage doesn't neccessarly have a pattern other than at the end they must equal the total voltage (which is 60V).
Steve- NH Member
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if all the paralels are the same then wouldn't r6 be 15?
if the r1 r3 r4 r5 were worth 15 then then the circuit would end with 60v and to get to r5 the volts have to go through r6
if the r1 r3 r4 r5 were worth 15 then then the circuit would end with 60v and to get to r5 the volts have to go through r6
Ahmed- NH Admin
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But the problem is tha they are not all parallel, its paral and series
This is the correct notation:
R1||(R2+R3||[(R8+R9)||R7+R5||(R4+R6)])
** "||" =the parallel sign
This is the correct notation:
R1||(R2+R3||[(R8+R9)||R7+R5||(R4+R6)])
** "||" =the parallel sign
Doc- NH Member
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I swear some ppl were doing this in physics ...
Hassan- NH Retired Moderator
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I am really sorry bro I can not help with this one. Have not taken physics for like at least 4 years....Good Luck in finding the answer.
Ahmed- NH Admin
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The problem is that this isn't physics, this is electricity. SCREW IT!!!
Doc- NH Member
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Hassan wrote:I am really sorry bro I can not help with this one. Have not taken physics for like at least 4 years....Good Luck in finding the answer.
9.8m^2
Ahmed- NH Admin
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Sayf, what?
wilku_88- NH Member
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UR6= Ucc * R6 / (R4+R6+R7) and the Ucc is the battery voltage... simply voltage divisor 
Doc- NH Member
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Ahmed IV wrote:Sayf, what?
lol nothing ...
Ahmed- NH Admin
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wilku_88 wrote:UR6= Ucc * R6 / (R4+R6+R7) and the Ucc is the battery voltage... simply voltage divisor
Well I got it wrong
(and so did the whole class)The answer is 12.1 V
I put 10.6V
Wilku I did it your way, and you get 20V, doing it your way, so its also wrong
wilku_88- NH Member
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Did you have value of resistor's and battery voltage?
Ahmed- NH Admin
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Yes:
R4=1000 ohms
R5=560 ohms
R6=1000 ohms
R7=1000 ohms
Total Voltage=60 Volts
R4=1000 ohms
R5=560 ohms
R6=1000 ohms
R7=1000 ohms
Total Voltage=60 Volts
wilku_88- NH Member
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There is one dot missed on that cicuit diagram now the answer is:
I think the answer is good
now the answer is:
I think the answer is good
Ahmed- NH Admin
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Wait 
What is the answer exactly, I am lost :scratch:
What is the answer exactly, I am lost :scratch:
wilku_88- NH Member
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Answer is UR6 on the right side of the picture I can't calculate that becouse I don't have value of R8 and R9.You must calculate R789=R7||(R8+R9) and R456=R5||(R4+R6) now you can calculate Up=UR4+UR6 and then UR6=Up* R6/(R4+R6). Do you get it now? 
I can't calculate that becouse I don't have value of R8 and R9.You must calculate R789=R7||(R8+R9) and R456=R5||(R4+R6) now you can calculate Up=UR4+UR6 and then UR6=Up* R6/(R4+R6). Do you get it now?
Ahmed- NH Admin
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Look this time Ill give youe veerything:
R1=560 ohms
R2=56 ohms
R3=910 ohms
R4=1000 ohms
R5=560 ohms
R6=1000 ohms
R7=1000 ohms
R8=560 ohms
R9= 560 ohms
Total Volts= 60 Volts
Electricity is so confusing.
R1=560 ohms
R2=56 ohms
R3=910 ohms
R4=1000 ohms
R5=560 ohms
R6=1000 ohms
R7=1000 ohms
R8=560 ohms
R9= 560 ohms
Total Volts= 60 Volts
Electricity is so confusing.
wilku_88- NH Member
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I calculate this and I have answer UR6 = 13,58V I check this on simulation in Electronic Workbench 5.0
Ahmed- NH Admin
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Your circuit looks different than mines...does it matter?
wilku_88- NH Member
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What's the different? Do you mind missing R2? I draw that circuit according to your instruction:
Ibn Rushd wrote:
This is the correct notation:
R1||(R2+R3||[(R8+R9)||R7+R5||(R4+R6)])
** "||" =the parallel sign
Ahmed- NH Admin
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Yes, that si the correct notation
^^^But, this is the correct circuit...
^^^But, this is the correct circuit...
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