In right triangle PQD: tan47=h/y ---->h=ytan47 [1]

In right triangle PQE: tan36=h/x ---->h=xtan36 [2]

Equate [1] and [2]: ytan47=xtan36 ------->y=tan36x/tan47 [3]

In right triangle DQE: x^2+y^2=70^2

Substitute [3]: x^2+ (tan36x/tan47)^2= 4900 ---> x^2(tan^2(47)+tan^2(36))/tan^2(47))=4900

x= 70tan47/ sqr root:tan^2(47)+tan^2(36)

Substitute into [2]: h=tan36/tan47 * 50tan47/ sqr root:tan^2(47)+tan^2(36)

And the answer is 39.26304499 (I calculated it wrong the first time)

Where is point Q? Can you draw your triangle with all the angles labeled please?

The reason I am asking is because i think you did it wrong.

I already did on the previous page

Fine Ahmed. If you solve this i officially will says you are better then i am for now.

team 1 and team 2 work on a project for 15 days. team 3 then comes to help them which the project was done in 5 days. the daily output of the 2nd team is 20 percent more than that of the 1st team. the second and 3rd team could do the jobs in .9 the time the first and third team to do it together. How much time would it have taken if all three teams worker together in the start?

I hate these world problems...Ill solve it after the AP exam lol

Good luck with your APs...

Thanks. Good luck to both of us on the Regents and SATs.