how did u do that?

just take orgo .. it'll prepare you for college orgo ..

How did I do what?

nevermind ...

so you guys think that evaluating ∫3x-2/√x dx is easier than finding the freezing point of something?

Let me post it again:

AP Chemistry: This lab based course will prepare students for the AP Chemistry Examination in May through which students may earn college credit. Topics include: the Structure of Matter (Atomic Theory & Structure, Chemical Bonding, Nuclear chemistry), States of Matter (Gases, Liquids and Solids, Solutions), Reactions (Reaction Types, Stoichiometry, Equilibrium, Kinetics, Thermodynamics), Descriptive Chemistry (Chemical Reactivity, Relationships on the Periodic Table, Introduction to Organic Chemistry—hydrocarbons and functional groups), and Laboratory Chemistry.

Modern Instrumental Chemical Analysis: (MICA) Rotational, vibrational, and electronic states of atoms and molecules. Interaction of radiation with atoms and molecules. Molecular symmetry. Electronic, rotational and vibrational spectroscopy. Chemical identification by joint applications of spectroscopic techniques such as IR, HNMR, C13-NMR, Mass Spec and UV Spec.

Quantitative Analysis: An introduction to the principles and calculations of quantitative analysis. Topics include: chemical stoichiometry, acid and base concepts, ionic equilibria, acid-base titrations, spectrophotometry, oxidation-reduction reactions, complex compounds, gravimetric analysis, and precipitation titrations. Laboratory work consists of elementary gravimetric, volumetric and instrumental analysis.

Organic Chemistry: Chemistry of organic molecules: structure, nomenclature, properties and reactions of carbon compounds with emphasis on aliphatic compounds. Introduction to reaction mechanisms and stereochemistry. Includes laboratory involving methods for preparation, isolation and purification of typical organic compounds. Experiments chosen to illustrate basic techniques.

why are posting it agian and again?

I just re-posted it once. Just in case someone else wants to see it...

so you guys think that evaluating ∫3x-2/√x dx is easier than finding the freezing point of something?

"finding the freezing point of something?"

That isn't chem. Chem has tons of other units.

um yeah that is chem buddy ...

No, I'm in AP Chem and I say no...so far we took 8.5 Chapters...

u have like 6 more months of school man ... and i had to do that in gen chem 2 so how are you telling me you dont do that in chem?

Sultan Ahmed-Lion Heart wrote:

"finding the freezing point of something?"

That isn't chem. Chem has tons of other units.

I said that isn't what all of chem is about...

Sayf, math is definately easier than anything......I haven't taken a chem course yet but i'm taking AP biology and it has a lot of chem in it!...i hate it!!!! haha
...and Ahmed that description is soooooo boring hahaha

i'm doing organic chem at the moment.
I FAIL...
HAHAHAAAAAAAAAAAAA!!
thats petroleum engineering out of da window...

Marwa wrote:

i'm doing organic chem at the moment.
I FAIL...
HAHAHAAAAAAAAAAAAA!!
thats petroleum engineering out of da window...

benzene ring hahaha

I love organic chem. I changing my name to "Oragnic Ahmed" very soon.

I organic chem !!!!

the hell with that chem test .. this is what happens when you have a retarded teacher .. everybody phayls

Sayfullah wrote:

so you guys think that evaluating ∫3x-2/√x dx is easier than finding the freezing point of something?

∫3x-2/√x
=∫(3x-2)x^-1/2
=∫(3x^1/2)-(2x^-1/2)
=[(3x^3/2)/(3/2)]-[(2x^1/2)/(1/2)]+c
= [2x^3/2]-[4x^1/2]+c ===>#

heheheeeeeeeeeee
that was easy...
unless its completely wrong..

Sayfullah wrote:

the hell with that chem test .. this is what happens when you have a retarded teacher .. everybody phayls

Apparently you failed English too

Marwa wrote:

Sayfullah wrote:

so you guys think that evaluating ∫3x-2/√x dx is easier than finding the freezing point of something?

∫3x-2/√x
=∫(3x-2)x^-1/2
=∫(3x^1/2)-(2x^-1/2)
=[(3x^3/2)/(3/2)]-[(2x^1/2)/(1/2)]+c
= [2x^3/2]-[4x^1/2]+c ===>#

heheheeeeeeeeeee
that was easy...
unless its completely wrong..

lol wrong

Sayfullah wrote:

Marwa wrote:

Sayfullah wrote:

so you guys think that evaluating ∫3x-2/√x dx is easier than finding the freezing point of something?

∫3x-2/√x
=∫(3x-2)x^-1/2
=∫(3x^1/2)-(2x^-1/2)
=[(3x^3/2)/(3/2)]-[(2x^1/2)/(1/2)]+c
= [2x^3/2]-[4x^1/2]+c ===>#

heheheeeeeeeeeee
that was easy...
unless its completely wrong..

lol wrong

1/2 √x(3x^(3/2)- 8 )??? o.o

BTW, if it's right...wolfram .

Sayfullah wrote:

Marwa wrote:

Sayfullah wrote:

so you guys think that evaluating ∫3x-2/√x dx is easier than finding the freezing point of something?

∫3x-2/√x
=∫(3x-2)x^-1/2
=∫(3x^1/2)-(2x^-1/2)
=[(3x^3/2)/(3/2)]-[(2x^1/2)/(1/2)]+c
= [2x^3/2]-[4x^1/2]+c ===>#

heheheeeeeeeeeee
that was easy...
unless its completely wrong..

lol wrong

wait...
emm da answer is
y=(3/2)x^2-4x^1/2+c ==>#
this has to be right man...
lolz

@Marwa: 1/2 √x(3x^(3/2)- 8 )

Sultan Ahmed-Lion Heart wrote:

@Marwa: 1/2 √x(3x^(3/2)- 8 )

how did ya get that man?
O.o

Sources...'Nuff said.